What is the ionization energy of Li in kJ mol?
520 kJ/mol
Ionization Energy is the Energy Required to Remove an Electron
| Element | Electron Configuration | First Ionization Energy IE1 |
|---|---|---|
| Lithium (Li) | [He]2s1 | 520 kJ/mol |
| Sodium (Na) | [Ne]3s1 | 495.5 kJ/mol |
| Potassium (K) | [Ar]4s1 | 418.7 kJ/mol |
What is the ionization energy of Li?
1st–10th ionisation energies
| Number | Symbol | 1st |
|---|---|---|
| 1 | H | 1312.0 |
| 2 | He | 2372.3 |
| 3 | Li | 520.2 |
| 4 | Be | 899.5 |
What is 1st ionization energy?
By definition, the first ionization energy of an element is the energy needed to remove the outermost, or highest energy, electron from a neutral atom in the gas phase.
Which element has a second ionization energy of 1577 kJ mol?
Si
Ionization Energies of Gaseous Atoms (kJ/mol)
| Atomic # | 2 | |
|---|---|---|
| 11 | Na | 4,563 |
| 12 | Mg | 1,451 |
| 13 | Al | 1,817 |
| 14 | Si | 1,577 |
Which has higher ionization energy Li or be?
If we see Be…it’s configuration is 1s2,2s2 so it needs to remove 2 electrons from it’s outermost shell to get stable. If we remove one electron from its outermost shell then it’s ionization energy would be more than Li because of the increased nuclear charge.
How do you determine electron configuration from ionization energy?
The distance of the electron from the nucleus: ionization energy decreases as the distance between the electron and the nucleus increases. Repulsion between electrons : ionization energy decreases if 2 negatively charged electrons are in close proximity to each other.
How is ionisation energy experimentally determined?
The ionization energy of a chemical element, expressed in joules or electron volts, is usually measured in an electric discharge tube in which a fast-moving electron generated by an electric current collides with a gaseous atom of the element, causing it to eject one of its electrons. …
Does Li or be have a greater ionization energy?
What is the second ionization energy of Li in 3635 kJ mol^-1?
If the first ionization energy of Li is 520kJ mol^-1 , the second ionization energy for Li in 3635 × x kJ mol^-1 . Find x .Given IE1 for H = 2.18 × 10^-18kJ mol^-1 .
What is the bond energy of HCl and Li in kJ/mol?
Given the following information (equations can be reversed, if necessary): Li (s) –> Li (g) heat of sublimation of Li(s) = 166 kJ/mol HCl (g) –> H (g) + Cl (g) bond energy of HCl = 427 kJ/mol
What is the standard enthalpy of glucose in kJ mol?
All standard enthalpies have the unit kJ/mol. As a brief reminder, here is the chemical reaction for the standard enthalpy of glucose: 6C(s, graphite) + 6H2(g) + 3O2(g) —> C6H12O6(s) Each standard enthalpy value is associated with a chemical reaction.
What is the electron affinity of Li (g) and Cl (g)?
Li (g) –> Li+(g) + e-ionization energy of Li (g) = 520. kJ/mol Cl (g) + e- –> Cl-(g) electron affinity of Cl (g) = -349 kJ/mol