What happens when potassium hydroxide reacts with acetic acid?

What happens when potassium hydroxide reacts with acetic acid?

Potassium Hydroxide is KOH and Acetic Acid is CH3COOH. The reaction between them is- KOH(aq.) On reaction between potassium hydroxide and acetic acid, a salt is formed. acetic acid + potassium hydroxide → water + potassium acetate.

What is the balanced equation for acetic acid and sodium hydroxide?

Note: Always remember that the balanced chemical equation between acetic acid and sodium hydroxide can be written as $NaOH + C{H_3}COOH \to C{H_3}COONa + {H_2}O$. It is called a neutralisation reaction.

What is the balanced net ionic equation for a reaction between acetic acid c2h3o2h and potassium hydroxide?

The proton from acetic acid should be moved to the hydroxide ion making the ionic equation:HC2H3O2aq + K+ + OH– → C2H3O2 – aq + K+ + H2O Turning this into a net ionic equation just means to remove the K+ spectator ions.

What is the balanced equation of acetic acid?

The chemical formula for acetic acid (vinegar) is CH3COOH. CaCO3 + CH3COOH –> H2CO3 + Ca(CH3COO)2. Step two of this equation involves the breakdown of carbonic acid into CO2 and water: H2CO3 = H2O + CO2. The overall reaction is the sum of these two reactions: 2CH3COOH + CaCO3 = H2O + CO2 + Ca(CH3COO)2.

What happens when acetic acid react with potassium hydroxide?

Acetic acid react with potassium hydroxide to produce potassium and acetate water. Potassium hydroxide – concentrated solution. Acetic acid – diluted solution.

What is the formula for dissolving potassium acetate in state of matter?

And state of matter should be normal text, on the same level as the formula (so dissolved potassium acetate is [noparse]CH 3 COOK (aq) [/noparse] – rendered as CH 3 COOK (aq)). This is incorrect. But I reasoned that CH 3 COO – is a weak acid so all of the things in the textbook about not dissociating 100% must come into play here.

Why are K+ and CH3COO-dissociate in the ionic equation?

In the ionic equation, K+ and CH3COO- are dissociated because CH3COOK is a strong electrolyte. While CH3COOK is a weak acid so it doesn’t dissociate 100%. Is this correct. I’m surprised the text doesn’t explain this.

Is CH3COOH a weak acid or strong electrolyte?

I meant to say CH3COOH is a weak acid, not CH3COOK. My idea is that CH3COOK is a strong electrolyte so it dissociates 100% in solution therefore leaving K+ and CH3COO- in solution. This part was OK, I just tried to answer your other question.